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7n^2-13n-30=0
a = 7; b = -13; c = -30;
Δ = b2-4ac
Δ = -132-4·7·(-30)
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{1009}}{2*7}=\frac{13-\sqrt{1009}}{14} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{1009}}{2*7}=\frac{13+\sqrt{1009}}{14} $
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